(3^2x)+(3^x+1)=10

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Solution for (3^2x)+(3^x+1)=10 equation: 



(3^2x)+(3^x+1)=10

We move all terms to the left:

(3^2x)+(3^x+1)-(10)=0

We get rid of parentheses

3^2x+3^x+1-10=0

We add all the numbers together, and all the variables

3^2x+3^x-9=0

We move all terms containing x to the left, all other terms to the right

3^2x+3^x=9

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